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Graduate Sum or upped bound of geometrico-harmonic series
Hi, I need help to determine the upper bound of this infinite series. \sum_{k=p+1}^{\infty} \frac{1}{k} a^k \ \ \ \ ; a \leq 1 The paper I am reading reports the upper bound to be, \sum_{k=p+1}^{\infty} \frac{1}{k} a^k \leq \frac{1}{p+1}\sum_{k=p+1}^{\infty} a^k = \frac{1}{p+1} \cdot...- aamir.ahmed
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- Bound Series Sum
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- Forum: Linear and Abstract Algebra