Sorry for misunderstanding.
So in the example above, there are 4C2 pairs of events which can be equal in 3 ways, then accounting for the last two elements having 2 and 1 outcomes we get (4C2)(3)(1)(2).
Is that it?
This is where I get confused with most problems in combinatorics. It...
Ooooh, it's starting to make sense. Thanks for your patience.
I'll try again.
4C2 gives the number ways that two elements could meet some criteria. There are 3 values that these two elements could have, and 2 values for the next and 1 for the last. Is that why it is (4C2)x2x3?
Dang. Can you help me understand what I missed?
I've been having a lot trouble thinking through the logic of these types of problems.
4C2=6 gives number of ways the experiment could repeat outcomes. 4C2(2)(2)=24 gives the number of sets in which two outcomes repeat, but this is...
Awesome!
So from what I understand:
4C2 gives the number of ways the experiment could repeat itself (the number of ways certain elements in the set could meet specific criteria). Then I multiply 4C2 by the possible outcomes for the other two elements. Since one of the three outcomes has...
Homework Statement
An experiment has 3 outcomes. If the experiment is performed 4 times, how many sets of outcomes exist in which exactly two of the experiments had the same outcome.
The Attempt at a Solution
From what I understand there is a 4-element set with each element having 3...
Awesome! I forgot all about the sets with neither. So:
5C2*2C1+5C3 gives the answer I was looking for. Since 5C3 is the number of sets which contain neither person and 5C2*2C1 are the sets with either.
So I needed to think about which groups contained either, and which contained neither...
Homework Statement
There is a group of 7 people. How many groups of 3 people can be made from the 7 when 2 of the people refuse to be in the same group?
Homework Equations
nCr
The Attempt at a Solution
Here is what I know:
7C3 gives the total number of groups that can be...
I had a tedious time understand the precise definition of a limit too. Here is how I had to think about it; maybe it will work for you.
Limx→a f(x) = L
We know that the limit of a function at a is the value f(x) approaches as x approaches a. To prove this mathematically we employ a few...
Thanks for the response. I spent yesterday looking into the subjects you listed and applied mathematics describes what I like most about math. Granted it's spread across a variety of fields...
I guess I'll just keep studying calculus, try to enroll in college, and go from there.
Thanks...
Hello all. I got curious about how fractions worked back in Feb 2012; I really enjoyed trying to understand it so I kept going and now I'm up to Limits at Infinity.
I really enjoy math and the mechanics of it (although most of it so far seems to be manipulating notation, or concept driven...