Recent content by Adam_9333

I am little confused, my calculus skills stayed in first year. Do put 0.02 in the x term on the left side of the equation also, and just solve for V?

Homework Statement need to solve for v? I also know the value of x=0.02 Homework Equations v(x)= 47.8 ⋅ (0.451/x)^(5.39) The Attempt at a Solution how do I take the log of both sides, is that the right approach to solve for v?

Thank you for the responses, I appreciate it! so I figure out how much energy it takes for 1kg of ice to go from -10c to 20c and then I can use that relationship to figure out mass with 650EJ?

I am not given any mass information so I cannot find Q of each step. any way to combine the equations? like Q= (m)(c)(t) + (m)(f)

Homework Statement transfer 650 EJ (10^18 joules) into an ice cube of unknown size. the temperature of h20 increases from -10c to 20c. Given: 1) q=mc(t2-t1) 2) for phase change q=m(F) specific heat of ice (c)= 2.22x10^3 J.kg^-1.K-1 heat of fusion (f)= 3.33x10^5 J/kg specific heat of water (c)...

Awesome thanks for the help, I really appreciate it!

yes exactly

Homework Statement solve for b given; (a) = time (seconds) (b) = height (meters) (c) = Velocity (seconds) Homework Equations b^2 = a^2 x c^2 / 4 The Attempt at a Solution If I take the square of the other side will I get? b = (a)(c) / 2 Thanks!