transfer 650 EJ (10^18 joules) into an ice cube of unknown size. the temperature of h20 increases from -10c to 20c.
2) for phase change q=m(F)
specific heat of ice (c)= 2.22x10^3 J.kg^-1.K-1
heat of fusion (f)= 3.33x10^5 J/kg
specific heat of water (c) = 4186 J.kg^-1.K^-1)
what is the side length and mass of cube?
The Attempt at a Solution
First I would use eqn 1 for the heating of ice from (-10C to 0C): q=650EJ, c t= 10C and solve for mass?
then use second equation for phase change solid to liquid (0C) using q=650,f and also solve for mass?
use eqn 1 again and solve for m of water going from (0C to 20C) q=650EJ, c, t=20c
Then I would sum the masses and solve for volume?