I understand what you’re trying to say. I have one more subquestion: if a rotating body has positive z-projection of angular position of let’s say ##20 \pi ## radians and it turns in the counter-clockwise direction for ##20 \pi## radians, If I am correct its angular displacement is zero. Should...
That’s why I made this thread. I’ve seen in some problems and equations that it can (it has to) to be larger than 2 pi. The only thing I still don’t understand is how would you explain it geometrically. Also, how do you differ angular displacement from angular distance? It seems logical to me to...
If someone hypothetically asked you what is angular displacement and which values can it have, what would you answer? Doing problems and understanding something deeply aren’t really the same things, I guess? Some textbooks are more math based and learning the important equations is probably...
What I got from this thread is an explanation that angular displacement can have values “whichever you need for the problem”. At least it seems like that, maybe I missed the point? If there wasn’t the “general case” for such basic stuff, learning physics would be half memorizing or let’s say...
In the specific case you mentioned, I wouldn’t reduce it. What I am trying to say is that by being driven by the logic, I could (probably) solve any textbook problem. However, I am more interested about the general case
If we think of simple case of spinning wheel, would it make sense? Indeed you would reduce 20 radians to zero because angle between initial and final position vector is, indeed, zero? An arbitrary point on wheel would return to its initial position after every full rotation. Angular distance...
Angular displacement is defined as the angle between initial and final radius vector of some arbitrary point on an object undergoing rotation. I’ve seen that some problems include angular displacement bigger than 2 ##\pi## radians. Also, I would note this example:
Let us start with definition...
I will point something out. Weight is defined, here where I live, as the force that object exerts on other objects when it’s standing (for example on soil or a box) / attached to rope. I don’t think astronomers can stand? In that case they do not exert “weight” on other objects.
However I...
The idea used here is that “Earth’s force of gravity” works as a concept only very close to the surface of Earth. It happens to work this way:
##F_g = mg##
where ##g## is the strength of Earth’s gravitational field:
##g = G \dfrac{M}{R^2}##
As long as there is no additional height ##h##...
It is only equal in inertial frame of reference when there object is perpendicular to the flat surface or directly attached to rope.
I am not from the USA / UK and here we have kinda different terminology. Weight is usually considered to be the pulling force exerted on rope / force that body...
Instantaneous velocity is defined as the first derivative of displacement with respect to time:
##\vec{v} = \dfrac{d \vec{r}}{dt}##
However, instantaneous velocity is also defined as the first derivative of function of distance with respect to time:
##v = \dfrac{ds}{dt}##
Why do these two...