Yeah, I got that at first too, but if you notice from the 'trick question', it's 2.00C4 = 4.7, and with algebra is 2.35. Then 2.00C2 = 2.00C4 = 2.35 as well.
I got the equivalent capacitance of the circuits correct, and the charge is also correct. It's just the potential over the resistors...
http://i.imgur.com/WhOXp.png
Here is a better view of the circuit.
Sorry, it is 12 V, not 14 V.
I thought at first that I could make a small loop just across R4 and R5, but that didn't work out, probably because it has to be wired through both since they are essentially connected in a...
Homework Statement
A 20.0 V battery is connected across capacitors of capacitances C1 = C6 = 2.9 μF and C3 = C5 = 2.00C2 = 2.00C4 = 4.7 μF.
http://imgur.com/ssxTC
What are
(c) V1 and (d) q1 of capacitor 1,
(e) V2 and (f) q2 of capacitor 2,
(g) V3 and (h) q3 of capacitor...
Homework Statement
An ideal battery with an emf of = 14.0 V is connected to a network of resistances with R1 = 6.00 , R2 = 12.0 , R3 = 4.00 , R4 = 3.00 and R5 = 5.00 . What is the potential difference across R5?
__R1__
__________R3__
__R2__
__R4_____R5__
__emf battery__...