Recent content by agadag

sorry, i don't know what that means. Terrible at physics...

Homework Statement A bubble with a volume of 1.00 cm3 forms at the bottom of a lake that is 40 m deep. The temperature at the bottom of the lake is 10°C. The bubble rises to the surface where the water temperature is 31°C. Assume that the bubble is small enough that its temperature always...

Homework Statement A cylinder contains 270 L of hydrogen gas (H2 at 0.0 C) and a pressure of 10 atm. How much energy is required to raise the temperature of this gas to 31°C? (answer needs to be kJ) Homework Equations PV =nRT and Q= MCT The Attempt at a Solution PV = nRT==> M=...

Homework Statement The displacement (in meters) of a wave is y = 0.13 sin(t - 3.82x), where t is in seconds and X is in meters. (a) Is this wave traveling in the +x or -x direction? 1.+x direction. 2.-x direction (b) What is the displacement y when t = 26.5 s and x = 6.4 m...

yea i got 10.76. Its not right...

ok. so i set the to two pressures equal to each other so i got P(oil)=P(mercury) (.91)(980)h = (980)(.72)(13.6) solved for h, and provided my answer in cm but its not right :\

Homework Statement A manometer using oil (density 0.91 g/cm3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases by 0.72 cm of Hg. (a) By how much does the fluid level rise in the side of the manometer that is open to the atmosphere? (b) What would your...

OMG THANKYOU. That did the trick. They wanted us to use density of 1024 for water in a previous problem so i was still using that. Thanks for all your help!

ok that's what i was thinking. So i did .262/9.8 to get the mass as .0267. Then I divided this by the volume (3.87 × 10-5 m3 ) to get the density of alcohol. Then i divided that density by the density of water (1024), to find the specific gravity. ...its not correct...:(

so shouldn't that just mean that I should be able to use .0773 kg / 3.87 × 10-5 m3 to get the density of alcohol??

hmm. so i do i subtract out the mass of the aluminum cylinder (.104) from the apparent wieght in alcohol and then use the new mass in my calculation (m/v)/density of water?

ok...soooo since weight = m x g do i divide by 9.8? sorry I am retarded when it comes to conversions...

Thanks cepheid...that makes sense. I had totally forgotten the density = m/v formula. I have another question that has been troubling me regarding specific gravity... An aluminum cylinder weighs 1.02 N. When this same cylinder is completely submerged in alcohol, the volume of the displaced...

@Sean -Ahhh that works perfectly. I have no idea what i did tho. lol

Homework Statement Accomplished silver workers in India can pound silver into incredibly thin sheets, as thin as 3.00x10-7 m (about one hundredth of the thickness of this sheet of paper). Find the area of such a sheet can be formed from 1.39kg of silver? (For the density of silver use the...