Recent content by agadag

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    A cylinder containing hydrogen gas

    sorry, i don't know what that means. Terrible at physics...
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    Volume of Bubble at Bottom of Lake: 1.00 cm3

    Homework Statement A bubble with a volume of 1.00 cm3 forms at the bottom of a lake that is 40 m deep. The temperature at the bottom of the lake is 10°C. The bubble rises to the surface where the water temperature is 31°C. Assume that the bubble is small enough that its temperature always...
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    A cylinder containing hydrogen gas

    Homework Statement A cylinder contains 270 L of hydrogen gas (H2 at 0.0 C) and a pressure of 10 atm. How much energy is required to raise the temperature of this gas to 31°C? (answer needs to be kJ) Homework Equations PV =nRT and Q= MCT The Attempt at a Solution PV = nRT==> M=...
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    Displacement of a traveling wave

    Homework Statement The displacement (in meters) of a wave is y = 0.13 sin(t - 3.82x), where t is in seconds and X is in meters. (a) Is this wave traveling in the +x or -x direction? 1.+x direction. 2.-x direction (b) What is the displacement y when t = 26.5 s and x = 6.4 m...
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    Solving for Pressure Rise in Manometer with Oil & Mercury

    ok. so i set the to two pressures equal to each other so i got P(oil)=P(mercury) (.91)(980)h = (980)(.72)(13.6) solved for h, and provided my answer in cm but its not right :\
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    Solving for Pressure Rise in Manometer with Oil & Mercury

    Homework Statement A manometer using oil (density 0.91 g/cm3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases by 0.72 cm of Hg. (a) By how much does the fluid level rise in the side of the manometer that is open to the atmosphere? (b) What would your...
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    How to Calculate the Area of a Thin Silver Sheet Using Density and Mass

    OMG THANKYOU. That did the trick. They wanted us to use density of 1024 for water in a previous problem so i was still using that. Thanks for all your help!
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    How to Calculate the Area of a Thin Silver Sheet Using Density and Mass

    ok that's what i was thinking. So i did .262/9.8 to get the mass as .0267. Then I divided this by the volume (3.87 × 10-5 m3 ) to get the density of alcohol. Then i divided that density by the density of water (1024), to find the specific gravity. ...its not correct...:(
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    How to Calculate the Area of a Thin Silver Sheet Using Density and Mass

    so shouldn't that just mean that I should be able to use .0773 kg / 3.87 × 10-5 m3 to get the density of alcohol??
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    How to Calculate the Area of a Thin Silver Sheet Using Density and Mass

    hmm. so i do i subtract out the mass of the aluminum cylinder (.104) from the apparent wieght in alcohol and then use the new mass in my calculation (m/v)/density of water?
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    How to Calculate the Area of a Thin Silver Sheet Using Density and Mass

    ok...soooo since weight = m x g do i divide by 9.8? sorry I am retarded when it comes to conversions...
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    How to Calculate the Area of a Thin Silver Sheet Using Density and Mass

    Thanks cepheid...that makes sense. I had totally forgotten the density = m/v formula. I have another question that has been troubling me regarding specific gravity... An aluminum cylinder weighs 1.02 N. When this same cylinder is completely submerged in alcohol, the volume of the displaced...
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    How to Calculate the Area of a Thin Silver Sheet Using Density and Mass

    @Sean -Ahhh that works perfectly. I have no idea what i did tho. lol
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    How to Calculate the Area of a Thin Silver Sheet Using Density and Mass

    Homework Statement Accomplished silver workers in India can pound silver into incredibly thin sheets, as thin as 3.00x10-7 m (about one hundredth of the thickness of this sheet of paper). Find the area of such a sheet can be formed from 1.39kg of silver? (For the density of silver use the...
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