Solving for Pressure Rise in Manometer with Oil & Mercury

AI Thread Summary
The discussion revolves around solving a manometer problem involving oil and mercury in response to a pressure increase in an air tank. The key equation used is P = rho * gravity * height, equating the pressures of oil and mercury. The user attempted to calculate the height of the oil column needed to balance a 0.72 cm mercury column but found their answer of 10.76 cm to be incorrect. It is noted that oil is significantly less dense than mercury, suggesting the expected height should be around 10 cm. The conversation highlights confusion over the calculations and the need for clarification on the correct approach.
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Homework Statement



A manometer using oil (density 0.91 g/cm3) as a fluid is connected to an air tank. Suddenly the pressure in the tank increases by 0.72 cm of Hg. (a) By how much does the fluid level rise in the side of the manometer that is open to the atmosphere? (b) What would your answer be if the manometer used mercury instead?

Homework Equations



P = rho*gravity*height

The Attempt at a Solution


I have looked at several options of solving this problem. None of them make any sense to me. Please help. Thankyou!
 
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The question is asking how high does a column of oil have to be to weigh the same as a 0.72cm column of mercury
 
ok.
so i set the to two pressures equal to each other
so i got P(oil)=P(mercury)
(.91)(980)h = (980)(.72)(13.6)
solved for h, and provided my answer in cm but its not right :\
 
If I'm reaing the question in the same way as you that should be correct (you can ignore 'g' it cancels)
The oil is roughly 15x less dense than mercury - so you should have an answer around 10cm (roughly)
 
yea i got 10.76. Its not right...
 

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