Recent content by agouti

Are you sure that is the whole question? That can't possibly be enough information to come up with an answer, surely... Without knowing anything about the string, we could assume that it was a ideal (lossless) carrier of the wave, so the "power" would be the energy taken to excite it -...

The answers given above by ObsessiveMathsFreak, namely that the average is \frac{\pi}{2} is wrong. The integral over a period will *not* give the average, merely the area under the curve, which should be obvious to everyone who provided the answers - as proof consider that the average of...