Recent content by ahm_11

∂p/∂x = constant Some boundary conditions: x=0 , x=L ... ∂u/∂x = 0 , v=0 , w=0 , ∂p/∂x = constant y=-a,y=a ... u=0,v=0,w=0, ∂p/∂y=0 z=-b,z=b ... u=0,v=0,w=0, ∂p/∂z = 0

The answer should be pi/4 ... from Fourier series we got ... t = \sum\frac{2}{n}(-1)n+1sinnt for t = \frac{\pi}{2} , \frac{\pi}{2} = 2 - 2/3 + 2/5 - 2/9 + ... which followed , \frac{\pi}{2} = 2 * \sum\frac{(-1)n+1}{2n - 1} hence, \sum\frac{(-1)n+1}{2n - 1} =...

μ[uyy + uzz] - ∂p/∂x = 0 ... (1) ∂u/∂x = 0 ; i tried assuming u(y,z) = Y(y)Z(z) so (1) becomes ... μ[ZYyy + YZzz] - ∂p/∂x = 0 hence (1/Y)*Yyy + (1/Z)*Zzz = (R/YZ) = -λ2 where, R = (1/μ)*∂p/∂x now Yyy + λ2Y = 0 ... can be solved easily but what about the remaining part ... i...

the solution should be ... y' = sinx - 2x4 + c1 y = -cosx - (2/5)x5 + c1x + c2

μ[uyy + uzz] - ∂p/∂x = 0 ... (1) ∂u/∂x = 0 ; now i assumed u(y,z) = Y(y)Z(z) so (1) becomes ... μ[ZYyy + YZzz] - ∂p/∂x = 0 hence (1/Y)*Yyy + (1/Z)*Zzz = (R/YZ) = -λ2 where, R = (1/μ)*∂p/∂x now Yyy + λ2Y = 0 ... can be...

[u][/yy] + [u][/zz] - ∂p/∂x = 0; ∂u/∂x = 0; ∂p/∂x = constant i tried separation of variables ...