Is My Integration Correct for y' = sinx - 2x4?

Student4 · Nov 2, 2011

Can anyone just help me integrate this 2 times. (with maple or somekind math program, or hand).

Equation d²y/dx² = cos x − 8x³, written as a second derivative of y with respect to x set equal to cos x minus 8x cubed.

Need to see if my 2 solutions is correct. :approve:

Mark44 · Nov 2, 2011

Student4 said:

Can anyone just help me integrate this 2 times. (with maple or somekind math program, or hand). Need to see if my 2 solutions is correct for this one.

View attachment 40636

Show us what you got.

Student4 · Nov 2, 2011

y'=sin(x)+2x^4+c
y=-cos(x)-2/5x^5+c

ahm_11 · Nov 2, 2011

the solution should be ...

y' = sinx - 2x⁴ + c₁

y = -cosx - (2/5)x⁵ + c₁x + c₂

Is My Integration Correct for y' = sinx - 2x4?

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