Recent content by AikiGirl

According to wiki it's I = (2mr^2)/5 So, 1/2 x 2/5 x 20^2 + 200 =9.8h 280=9.8h h=28.57m :D

I still can't get the right answer? Ek(rot) + Ek(lin) +Ep = Ek(rot) + Ek(lin) +Ep 1/2 Iw^2 + 1/2mv^2 +mgh = 1/2 Iw^2 + 1/2mv^2 +mgh 1/2 r^2(v^2)/(r^2) + 1/2 v^2 +0 = 0 + 0 + 9.8h 1/2 x 20^2 + 1/2 x 20^2 =9.8h 200+200 = 9.8h h=40.8m Is that right working??

Homework Statement "State what you would infer from each of the following observations and suggest experiments you would carry out to test the validity of your inferences: When an unpleasant smelling gas was bubbled into an orange solution of a substance 'A', a solid was formed and the mixture...

Homework Statement A uniform solid sphere rolls on a horizontal surface at 20m.s^-1 and then rolls up an incline which has an angle on inclination of 30°. Ignoring friction, calculate the height attained by the sphere. Homework Equations Weren't given any specific equations to work...