Recent content by Aisling1993

Hello, thanks for helping, so now Flux , phi = ∫B.dA = μ0μrNId^2/8 B=μ0(H + M) for the toroidal material but we have magnetic linearity so: Bc= μ0μrHc and Bg=μ0Hg where Bc and Hc represent the B-field and H-field in the toroid and Bg and Hg in the air gap. but the total flux...

Homework Statement A toroidal coil,with N turns of wire carrying a current I, is uniformly wound around a toroidal core that has a mean radius a, a cross-sectional area A= ∏(d/2)^2, and is made of a linear, isotropic homogeneous material with relative permeability μr. You may assume that the...