I figured it was an even function after I had posted this.
Thanks to both some_dude and uart for posting two different approaches to the problem. I understand this problem a lot better and have solved some similar now.
Thanks again,
Adam
I was working on the following problem from a textbook. The textbook has no answer. I have included my solution - I am not sure whether it is correct Any ideas and or solutions? (guidance)
Question:
Suppose that f is any function with domain (-infinity, +infinity)
a) Does the function g...
This sort of logic represented by mathematical equations is exactly what I was looking for. Thank you very much. I have written some maths down for Clausius-Clapeyron but I am not sure it is correct.
Can you explore Clausius-Clapeyron mathematically and I'll see if it matches with mine...
This answers the qualitative part of my question very well.
I would be happy if you could show me some mathematics behind Clausius-Clapeyron and Gibbs free energy i.e a full mathematical description.
Thanks,
Adam
I gather the following:
- A decrease in atmospheric pressure leads to a decrease in boiling point
- Thermodynamics explains this using mathematics
- A kinetic theory model can also be used to explain
I need to know:
- The science behind this occuring. Why does a lower atmospheric...
Thank you. It does allow me to picture what is going on.
I also gather that this can be descibed by Thermodynamics, mathematically?
If this is so could you show me how?
I understand that liquid water cannot exists on Mars for extended periods of time because:
a) The atmosphere is too thin
b) Resulting in a lower boiling point water
c) Which leads to sublimification of solid ice into gaseous vapour
Quite specifically, I would like to understand the...
Continuing with the titration of CaO
CaO + 2HCL >> CaCl2 + H2O
number of moles = m/mr = 0.375/56 = 0.00669642857
From equation, number of moles (HCL) = 2*0.00669642857 = 0.013938571
Therefore:
V = n/c = (0.0134/0.500)*1000 = 26.8cm3
Since there 85% of NaOH, the mass of NaOH in the 2.5g mixture is:
(85/100)*2.5 = 2.12500
Therefore the mass of CaO in the mixture is:
2.5 - 2.12500 = 0.375g
The titration of NaOH:
NaOH + HCL >> NaCl + H20
number of moles of NaOH = m/Mr = 2.12500/40 = 0.053125 mol
From equation number of moles...
Homework Statement
"Soda lime is 85.0% NaOH and 15.0% CaO. What volume of 0.500M Hydrochloric Acid is required to completely neutralise 2.50g of the Soda Lime?"
Hint: Consider the reactions separately
Homework Equations
Formation of Soda Lime:
CO2 + H2O >> H2CO3
H2CO3 + 2NaOH >>...
From a young age I was always very curious about the universe. I had to absolutely no everything about some system - how it worked and how different components interacted. It game me the feeling of being in control of the universe - I like to be the master of the universe!
Even now it's the...