Recent content by ajassat

I figured it was an even function after I had posted this. Thanks to both some_dude and uart for posting two different approaches to the problem. I understand this problem a lot better and have solved some similar now. Thanks again, Adam

I was working on the following problem from a textbook. The textbook has no answer. I have included my solution - I am not sure whether it is correct Any ideas and or solutions? (guidance) Question: Suppose that f is any function with domain (-infinity, +infinity) a) Does the function g...

This sort of logic represented by mathematical equations is exactly what I was looking for. Thank you very much. I have written some maths down for Clausius-Clapeyron but I am not sure it is correct. Can you explore Clausius-Clapeyron mathematically and I'll see if it matches with mine...

This answers the qualitative part of my question very well. I would be happy if you could show me some mathematics behind Clausius-Clapeyron and Gibbs free energy i.e a full mathematical description. Thanks, Adam

I gather the following: - A decrease in atmospheric pressure leads to a decrease in boiling point - Thermodynamics explains this using mathematics - A kinetic theory model can also be used to explain I need to know: - The science behind this occurring. Why does a lower atmospheric...

Thank you for the additional information here. Specifically:

Thank you. It does allow me to picture what is going on. I also gather that this can be descibed by Thermodynamics, mathematically? If this is so could you show me how?

I now understand why the atmosphere is thin! I still don't understand why a lower pressure reduces boiling point?

I understand that liquid water cannot exists on Mars for extended periods of time because: a) The atmosphere is too thin b) Resulting in a lower boiling point water c) Which leads to sublimification of solid ice into gaseous vapour Quite specifically, I would like to understand the...

It should be: 0.0133928571 Which when rounded to 3 sig fig is 0.0134 NB: See adjusted Calculation and answer

Adding the two calculated volumes gives total volume of HCL required = 26.8 + 106.25 = 133.05cm3 or 133cm3 (to 3 sig fig0 Borek: Please confirm :)

Continuing with the titration of CaO CaO + 2HCL >> CaCl2 + H2O number of moles = m/mr = 0.375/56 = 0.00669642857 From equation, number of moles (HCL) = 2*0.00669642857 = 0.013938571 Therefore: V = n/c = (0.0134/0.500)*1000 = 26.8cm3

Since there 85% of NaOH, the mass of NaOH in the 2.5g mixture is: (85/100)*2.5 = 2.12500 Therefore the mass of CaO in the mixture is: 2.5 - 2.12500 = 0.375g The titration of NaOH: NaOH + HCL >> NaCl + H20 number of moles of NaOH = m/Mr = 2.12500/40 = 0.053125 mol From equation number of moles...

Homework Statement "Soda lime is 85.0% NaOH and 15.0% CaO. What volume of 0.500M Hydrochloric Acid is required to completely neutralise 2.50g of the Soda Lime?" Hint: Consider the reactions separately Homework Equations Formation of Soda Lime: CO2 + H2O >> H2CO3 H2CO3 + 2NaOH >>...

From a young age I was always very curious about the universe. I had to absolutely no everything about some system - how it worked and how different components interacted. It game me the feeling of being in control of the universe - I like to be the master of the universe! Even now it's the...