Recent content by Aleolomorfo

Hello community! I am facing a conceptual problem with the correlation matrix between maximum likelihood estimators. I estimate two parameters (their names are SigmaBin0 and qqzz_norm_0) from a multidimensional likelihood function, actually the number of parameters are larger than the two I am...

Hello everybody! I am working on a code in which I need to study the dependence of ##<p_T>## vs ##p_L## (the average transverse momentum and the longitudinal momentum of a particle). I am looking for references, papers, books, etc. concerning this topic, but I have not been so lucky. My...

Hello everybody! I have a doubt about a reaction. $$ p + n \rightarrow \Lambda + \Sigma^+ $$ I have to establish if it is allowed or not. Charge is conserved (1 -> 1) Baryon number is conserved (2 -> 2) Strangeness is not conserved (0 -> -2) Third component of the isospin is not conserved (0...

Thank you for the reply. The attached diagram is better? The previous diagram is ##\mathcal{O}(\alpha_s^2)##, instead this one is ##\mathcal{O}(\alpha_s)##, isn't it? PS It is not homework, I was just discussing about Feynman diagrams with a mate of mine.

Hello everybody! I have to write the Feynman diagrams for the process ##\pi^- + p \rightarrow \Lambda_c^+ + D^-##. It is a strong process since all the quantum numbers are conserved. I have attached my attempt, is it correct? Thank you all in advance!

Hello everybody! Let's begin with the spin. Spin of the ##\Lambda## is ##1/2## and of the pion is ##0##: $$ \frac{1}{2} \otimes 0 = \frac{1}{2}$$ Since I know from the homework statement that ##L=1##: $$ \textbf{J} = \textbf{spin} \otimes \textbf{L} = \frac{1}{2} \otimes 1 = \frac{1}{2} \oplus...

Hello everybody! I join the conversation since I also have some doubts about Wu experiment. Yes, you are right, but if the emission is in the opposite direction of the spin the weak interactions obey V-A structure, otherwise V+A... So, the direction of the emission is important. From the...

$$|\rho^0> = |1,0> = \frac{1}{\sqrt{2}}|1,+1>|1,-1> + 0 |1,0>|1,0> - \frac{1}{\sqrt{2}}|1,-1>|1,+1> = $$ $$ =2\frac{1}{\sqrt{2}}|1,+1>|1,-1> + 0 |1,0>|1,0> = \frac{1}{\sqrt{2}}|\pi^+\pi^-> + 0 |\pi^0\pi^0>$$ From the Clebsch-Gordan coefficients I see that the decay in ##\pi^0\pi^0## is...

Hello everybody! I have a question regarding the forbidden decay ##\rho^0 \rightarrow \pi^0\pi^0##, but it is a general doubt. My book states that one of the reasons why the decay is forbidden is Bose-Einstein statistics, the final state of two equal pions must be in an antisymmetric state...

Hello George! Yes, we use three scintillators at the same time, one over the other. We record a start signal from the passage of a muon in the first and the second scintillator (the events we are interested in are the ones in which the muon stops in the middle scintillator). So the start...

Thank you very much!

I have attached the file with the set up. $$ p = (m_k, 0, 0, 0)$$ $$ k_1 = (E_{\nu},0,0, E_{\nu})$$ $$ k_2 = (E_{\mu}, 0,0, -\sqrt{E_{\mu}^2-m_{\mu}^2})$$ Using the conservation of momentum and energy I get: $$E_{\mu} = \frac{m_k^2+m_{\mu}^2}{2m_k} = 258.15 MeV $$ $$ p_{\mu} =...

No, we did not. We only used the dataset but I see your point, we should have used MC.

My first idea was to find an expression of the muon momentum as a function of the angle and then maximaze the expression. But my attempts were not succesful. I report here my attempt. Set up (referring to the attached file "bettini.pdf"): $$ p = (\sqrt{p_k^2+m_k^2},0,0,p_k)$$ $$ k_1 =...

Hello George Dowell, I have attached the final report where you can find the information you need. One thing to notice: last year the particle physics laboratory had too many students, so we were chosen to perform the measurement of the muon lifetime with electronic modules and scintillators...