Recent content by Alicia489

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    Undergrad Basic rule is that: a/b=c/d then, a+b/a-b = c+d/c-dbut suppose

    the above statement ofcourse.
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    Undergrad Basic rule is that: a/b=c/d then, a+b/a-b = c+d/c-dbut suppose

    micromass, thakyou for replying.My question is whether you can point out any mistake in it. and Mark44 Sorry for not putting it in the parenthesis.What i actually meant to post was (a+b)/(a-b) = (c+d)/(c-d).
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    Undergrad Basic rule is that: a/b=c/d then, a+b/a-b = c+d/c-dbut suppose

    Basic rule is that: a/b=c/d then, a+b/a-b = c+d/c-d but suppose if we apply "componendo dividendo" just to the RHS TWICE, we get the original number... consider the example : 16/4 (which we know is equal to 4 or rather 4/1) now applying componendo dividendo just once to 16/4 , we get...