Recent content by amal

I didn't follow you on the last post. Could You please give me some maths?

What I thought was, as force is a free vector, we could move it to the bottom of block or on the incline surface of wedge. The force is not normal to either surfaces. So, in that case, we generally take two components: one along the incline and one normal to it. Also, in any case, friction is...

Yes. I'll give it a shot. There is a wedge with 15 degrees wedge angle standing on rollers. The block placed is cut in such a way that it's bottom edge (the one which touches the wedge) is parallel to incline of the wedge. The block is placed in vertical channel and there are rollers in there...

Homework Statement...

I am clear now. Thank you very much ehild.

Homework Statement The problem, basically, is very simple but, it is confusing me. It says: "There is block on a moving train, which is being pushed by a man. The man applies force F to displace the block by s wrt Train. The moves S in that period. Find work done on the block by the force wrt...

Could you please explain in more detail?

Homework Statement Please check the enclosed figure. Find the force of compression in the wire loop. Magnetic field B is directed into the page and current i is flowing anti-clockwise. The radius of the wire loop is 'a'. Homework Equations \vec{F}=i\vec{l}\times\vec{B} The...

Amazing. The photo's too good.

they are same things. in second equation replace x by y and as the object is in free fall, initial velocity is zero.

How do you find this one?

By using Pythagoras, you can find the actual velocity of rain. And then use it in the next case. Here, as V of rain wrt man is perpendicular to ground, you can constuct a triangle to find actual velocity of rain.

I recently came across an odd phenomenon known as Mpemba effect. It says that hot water freezes quicker than cool water provided that temperature difference is not too much. E.g. it can be, say, 30 degrees Celsius and 50 degrees Celsius but not something like 99 and 1. Unfortunately, the book...

How did you get the equation (1)?

Try keeping ISO 800.,Decreasing shutter and increasing aperture by 1-2 stops.