Recent content by Andrew187

Just out of curiosity has anyone ever come across these questions before as I haven't covered even the basics of it in level 3 so I don't know how to tackle this problem this is a level 4 question.

On my first reaction I think that g sin\Theta is the total for the sin\Theta from the total and r2 is the radius of the disc which in this case is 750mm but I don't understand what k2 is?

Hi there I was wondering if someone can help me on this attachment I am stuck on question 1.3 and 1.4. This was an experiment to see relationship between sin and gradient I have confidently completed the first two questions but it is the last two questions which are troubling with I am finding...

Sorry what I was meant to say was solving the equation isn't really the problem because I can sit till the cow's come home calculating the unknowns I eventually get there but the bit I struggle with is writing the equations and drawing the correct diagram, because when I try to look at notes and...

Writing it shouldn't be a problem but solving the two equations from the two unknowns is a problem I know the answer but don't know how I solved it.

Isc= (9+25)*i1 - 25*i2 = 15 -25*i1 + (25+7)*i2 = 0 This Is the bit I didn't understand i took this out of my notes I know here that the value of I2=0.293a, but I didn't quite understand how I worked out I1.

That bits not the problem I don't know how I worked out the value for I1 and how I got Isc to 0.81a

7.032v/0.81a=8.68 ohm ?

I2 = 0.81a?

Isc= (9+25)*i1 - 25*i2 = 15 -25*i1 + (25+7)*i2 = 0

Ok we are getting there lol I just need a clue how to work out I1 as I believe I need that for the ISC?

Is the drawing correct?

I think its Isc? but for that I need to find I1 so how would I go about that?

V =IR= V= 0.293a*24Ω=7.032v

R8+R9+R10/ 0.293a= 25Ω+7Ω+24Ω/ 0.293a= 5.23v is that correct?