Recent content by andrewy77

I did try, however, multiplying (3.8-m) (560.-n)= (340.-n)(0.70mx) That answer was totally wrong. x- unknown

Homework Statement A non-uniform is 3.8-m long and has a weight of 560.-n. The bar is balanced in a horizontal position when it is supported at its geometric center and a 340.-n is suspended 0.70-m from the bar's light end. Sketch this system and find the bar's center of gravity...

Well, the problem states the rock was shot with 98.0 n of force, so I'm guessing it's the force applied to shoot the rock.

Yes; the diagram helped a little. For part a), I used f=ma Solving for a gets you a=f/m With the given data, I got 4900 m/s for a. That sounds a little quirky..

Thanks for the greeting! The problem doesn't say; therefore, I think the only force acting on it is gravity, which is 9.8 m/s. Well, given that m= f/a a= f/m. That is all the information he gave us.

Homework Statement A 0.0200-kg rock is shot directly upward with an average force of 98.0 n. The rock accelerates through a distance of 0.150 m. Homework Equations a.) Determine the acceleration while in the slingshot. b.) What is the velocity with which it leaves the slingshot? c.)...