Recent content by anglum

to find the mass of the contintent i would take Density = mass/volume 2680kg/m^3 = mass / (42000000m * 4200000m * 32000m) and then solve for mass and that gives me the mass in kg?

kinetic energy? a continent is 4200 km on a side and 32 km deep its mass density is 2680 kg/m^3 it is moving at an avg speed of 4.8cm/year what is its mass? answer in units of J what is its kinetic energy? answer in units of J a jogger with mass 75kg has the same kinetic energy as...

thanks again

for W did u use the equation sin10(73.007) + T3sin43 - W = 0 12.677 + (98.303)(.681998) - W = 0 12.677 + 67.042 = W W = 79.719484 N or 8.13464 kg?

so i solve for T3 in the horizontal and get 98.303N then plug that into the vertical and get W = 92.3971N or 9.428275kg are those the answers you got?

ok I am assuming this is what they should look like cos10(73.004) - T3cos43 = 0 HORIZONTAL sin10(73.007) + T3sin43 - W = 0 VERTICAL did i fix them

how should the plus minus signs be? and isn't the angle 43? for horizontal and vertical

what should the plus minus signs be? do i have the equations for vertical and horizontal right? i thought the angle on the problem was 43 degrees?

the horizontal force is cos10(73.004) + T3cos43 = 0 ??

and the vertical force on it is sin10(73.004) + W + T3sin43 = 0 ?

ok the horizontal force on the 2nd knot is ---- cos10 * 73.004 correct?

but once i have T1 and T2 how do i get T3 and the other weight?

yeah I am an idiot... when i solve that the right way i get T1 = 125.3455633 N then i can plug that in and solve for T2 and get T2 = 73.004N

my math has to be wayyyy off

so i then get .8159X -.57357x/.98480 = 90/.173648 then i get .8159X - .57357X = (90/.173648) * (.98480) .24233X = 510.4118677 T1 = 2106.267766 that can't be right?