Solving Tension Problem: Can't Find T1

[PhanthomJay]

and the vertical force on it is

sin10(73.004) + W + T3sin43 = 0

?

Yes, except watch plus and minus signs.

 

[anglum]

how should the plus minus signs be? and isn't the angle 43? for horizontal and vertical

 

[anglum]

ok I am assuming this is what they should look like

cos10(73.004) - T3cos43 = 0 HORIZONTAL

sin10(73.007) + T3sin43 - W = 0 VERTICAL

did i fix them

 

[learningphysics]

Yeah, those look right.

 

[anglum]

so i solve for T3 in the horizontal and get 98.303N

then plug that into the vertical and get W = 92.3971N or 9.428275kg

are those the answers you got?

 

[learningphysics]

so i solve for T3 in the horizontal and get 98.303N

then plug that into the vertical and get W = 92.3971N or 9.428275kg

are those the answers you got?

I get something different for W. But I get the same T3.

 

[anglum]

for W did u use the equation

sin10(73.007) + T3sin43 - W = 0

12.677 + (98.303)(.681998) - W = 0

12.677 + 67.042 = W

W = 79.719484 N or 8.13464 kg?

 

[learningphysics]

for W did u use the equation

sin10(73.007) + T3sin43 - W = 0

12.677 + (98.303)(.681998) - W = 0

12.677 + 67.042 = W

W = 79.719484 N or 8.13464 kg?

yeah that looks right.

 

[anglum]

thanks again