Not sure what you mean by which vector is directed 2.2° North of East and the question ask me which direction and how far she has to swim back to her starting point.
Well the way I came up with 2.2° north of east was adding the xy which gave me 240i+9.28j which puts it in the first quadrant and arctan ( 9.28/240) = 2.2°
Sorry, typo I didn't mean South of North I mean South of East since the x component is positive and and the y component is negative which make its in the 4th quadrant
I though my component were correct
90.0m N ----------------------------- 90cos90 = 0 90sin0=90-----------(0i + 90j)
200.0m E...
Homework Statement
A diver explores a shallow reef off the coast of Belize.
She initially swims 90.0 m north, makes a turn to the east
and continues for 200.0 m, then follows a big grouper for
80.0 m in the direction 30° north of east. In the meantime,
a local current displaces her by 150.0 m...
Ok I see the issue lol. so 4th quadrant positive x and negative y. Now I subtracted 360 from 60° to get 300. I'm assuming that's wrong so would I need to add 270 to the 60° or make it -60° this is where the confusion comes in
Im not understanding. for the first part, wouldn't 2.5 @ W45N = -1.77i + 1.77j . Sorry I am still new at this but if you draw a diagram for that part 1 x would be negative and y would be positive giving NW?
Can you explain for the first part what I am doing wrong just do I have an idea. I am really confuse when it comes to which quadrant and direction. For example sometime when something is in quadrant 4 some either takes 360 off the angle or add 270.
Homework Statement
In an attempt to escape a desert island, a castaway
builds a raft and sets out to sea. The wind shifts a great
deal during the day and he is blown along the following
directions: 2.50 km and 45.0° north of west, then 4.70 km
and 60.0° south of east, then 1.30 km and 25.0°...