- #1

Anonymous1135

- 13

- 1

## Homework Statement

In an attempt to escape a desert island, a castaway

builds a raft and sets out to sea. The wind shifts a great

deal during the day and he is blown along the following

directions: 2.50 km and 45.0° north of west, then 4.70 km

and 60.0° south of east, then 1.30 km and 25.0° south of

west, then 5.10 km straight east, then 1.70 km and 5.00°

east of north, then 7.20 km and 55.0° south of west, and

finally 2.80 km and 10.0° north of east. Use a graphical

method to find the castaway’s final position relative to the

island.

Ok so I am just doing this for fun getting ready for the spring semester trying to get ahead.

So the book is giving me 7.34km and 63.5 SW I am getting after multiple attempt 9.14km and 62.50SW

What am I doing wrong

## The Attempt at a Solution

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2.50km 45° NW is 135°

4.70km 60° SE is 300°

1.30km 25° SW is 205°

5.10km 0° E is 0°

1.70km 5° NE is 5°

7.20km 55° SW is 235°

2.80km 10° NE is 10°

**---------------------------------------------------------**

2.50cos(135) = -1.77

2.50sin(135) = 1.77

4.70cos(300) = 2.35

4.70sin (300) = 4.07

1.30cos(205) = -1.78

1.30sin(205) = -0.55

5.10cos(0) = 5.10

5.10sin(0) = 0

1.70cos(5) = 1.69

1.70sin(5) = 0.15

7.20cos(235) = -4.13

7.20sin(235) = -5.90

2.80cos(10) = 2.76

2.80sin(10) = 0.49

My answer is 4.22i - 8.11j 9.14km and 62.50SW