anuttarasammyak's latest activity
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anuttarasammyak replied to the thread A Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.Thanks. I will restate it to confirm my understanding. Here I try not to refer controversial (at least to me) tensor and concentrate on... -
anuttarasammyak replied to the thread A Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.First of all, thanks @JimWhoKnew So in general cases which could include ##\delta g^{\mu\nu}##, do we need further information or... -
anuttarasammyak replied to the thread A Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.I am sorry I don't understand "the same signature". If A is g itself, I think that B = A = g. A=mg, B=1/m g where m is a real number... -
anuttarasammyak replied to the thread A Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.Going back to basics, Dirac's textbook defines a tensor as follows: $$... -
anuttarasammyak replied to the thread A Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.I will summarize what I have written. The index-raising and -lowering relation for the metric tensor $$... -
anuttarasammyak reacted to JimWhoKnew's post in the thread A Is the variation of the metric ##\delta g_{\mu\nu}## a tensor? with
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Ordinarily, ##~T^{\mu\nu}~## , ##~T_{\mu\nu}~## and ##~T^\mu{}_\nu~## are coordinate representation of the same coordinate-free object... -
anuttarasammyak replied to the thread A Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.Thank you @JimWhoKnew for the clear and easy-to-understand explanation for the "anomaly". I have preffered to regard "new"... -
anuttarasammyak replied to the thread A Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.Thanks. Even with this general caution, may we take it obvious that in tensor division of $$ \bar{g}_{\mu\nu} := g_{\mu\nu}+\delta... -
anuttarasammyak replied to the thread A Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.In the world of metric tensor undertaking variation where the metric tensor is $$ \bar{g}_{\mu\nu} := g_{\mu\nu}+\delta g_{\mu\nu} $$... -
anuttarasammyak replied to the thread A Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.@haushofer it is a good chance to learn from your comments. May I say that in GR when tensor ##A_{abc..}^{def...}## is written... -
anuttarasammyak replied to the thread A Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.@haushofer Thanks for the teaching. $$ g_{\mu\nu}+\delta g_{\mu\nu} =( g_{\alpha\nu}+\delta g_{\alpha\nu}) (g_{\mu\beta}+\delta... -
anuttarasammyak replied to the thread A Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.No, I don't know any case in tensors. That is one of the reasons that I think : I am afraid that you are against it in post #11... -
anuttarasammyak replied to the thread A Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.@haushofer The equation is the application of the rule for raising and lowering the indices in use of the (varied) metric tensor to the... -
anuttarasammyak replied to the thread A Is the variation of the metric ##\delta g_{\mu\nu}## a tensor?.Under variation of metric tensor, ##g_{\mu\nu}+\delta g_{\mu\nu} ## is a tensor but its parts ##g_{\mu\nu}## and ##\delta g_{\mu\nu} ##... -
anuttarasammyak replied to the thread A Reconciling units for the Einstein and Landau-Lifshitz pseudotensors.Why don't you start with the familiar case that all $$x^0,x^1,x^2,x^3$$ have dimension of length. All the metric tensor components, thus...