anuttarasammyak's latest activity

With no loss of generality a<b $$f:=\ln \frac{b^a}{a^b}=ab(\frac{\ln b}{b}-\frac{\ln a}{a})$$ Sign of f decides which is larger. The...

They are the same because g is a symmetric tensor.

I noticed the following question generated quite a lot of interest on the Internet. Which is larger ##e^{\pi}## or ##\pi^e##? Most (if...

If the goal is to learn about the 1s state of the electron, then you are of course correct that performing two position measurements...

The pair of events I would refer is I should have stated clearly that measured space coordinate values of the electron are used to...

We don’t. Proper time is the length of a path through spacetime between two events; the electron has no path or position so the notion...

Quantum field theory treats the decoherence between the system and the measuring apparatus, but does it not fail to account for the...

You are conflating a bunch of different things here. Much of what you mention above (probability as squared amplitudes, role of...

This is my conjecture about QFT that I learned from this thread and some othre readngs: In quantum field theory (QFT), measurement is...

Am I correct in understanding that both ⟨v⟩ = ⟨p⟩/m and ⟨v⟩ = d⟨x⟩/dt are valid in the non-relativistic regime for a free particle?　 If...

No position means no path along which we can integrate to find the proper time. Instead we use QFT and calculate an amplitude for a...

I have read that in relativistic quantum theory the decay rate is computed from the weak-interaction matrix element using the...

Thank you. Re:#30 Can we call ##\frac{<p>}{m}##, relativistically ##<\frac{pc^2}{E}>, ## as well as ##\frac{d}{dt}<x>(t)## the...

So even in free space QM tells us nothing about velocity ?

Cosmic-ray muons correspond to wave packets in free space, and their lifetime extension can be explained by the Lorentz factor. Muons in...