Recent content by anuttarasammyak

dP dV is infinitesimal of second order. We can disregard it in calculation.

Generalizing 2 to integer n, the equation is $$x^2-nx+1=0$$ $$x=\frac{n \pm \sqrt{n^2-4}}{2}$$ So we know for x to exist ##|n|\geq 2## $$x=\frac{n + \sqrt{n^2-4}}{2}$$ for n>2 because x > n - 1/n. $$x=\frac{n - \sqrt{n^2-4}}{2}$$ for n<-2 because x < n - 1/n. Is it right ?

Say RHS continued fraction is x, we have an equation $$x=2-\frac{1}{x}$$ $$(x-1)^2=0$$ $$x=1$$ So we know if x converges, x=1. If it does not converge the equation is not satisfied. Thus x should converge and x=1.

https://en.wikipedia.org/wiki/Newton_polynomial shows : The matrix is downer triangular matrix. Solving it from the top law and getting to know ##\{a_0,a_1,..a_n\}## Then we get ##a_{n+1}##.

Thanks for the teaching and clarification. Now I guess: 1. In case that the metal disk is all white, i.e. no magnets at all, emf V=0 2. In case that the metal disk is all red, i.e. magnets all around, we will observe emf V ##\neq## 0. 3. In case that the metal disk is made of half red...

Thanks for the explanation for confirmation I also draw a sketch. A is a contact point of the disk. The path OA matters. When A is on white half disk edge, there is no B through line OA, emf V=0. When contact A is on red haldf disk edge, the pass OA could be on the B spots thus v X B 's...

In order to understand the configuration correctly, could you provide a sketch of your experiment?

n qubit has 2^n base with complex coefficients so they have 2^(n+1) real parameters. Normalization and the extra phase factor reduce 2 so we should have 2(2^n-1) dimension real manifolds or 2^n-1 complex manifolds to express n qubit states. For coefficients ##\{\ r_je^{i\phi_j}\}##, the...

You may do this substitution anywhere. Just please be careful for taking derivatives as I posted #2.

In case there exists external E field, permanent or instantaneous by fluctuation, atomic dipole moment would appear to lower the system energy.

##p^2=2m\epsilon## ##2pdp=2md\epsilon## ##dp=\frac{m}{p} d\epsilon=\frac{\sqrt{m} }{\sqrt{2}\sqrt{\epsilon}} d\epsilon## it differs factor 1/2 from your result.

I guess that at the neck the wormhole the angular velocity of the body increases by the law of angular momentum conservation, but its velocity cannot exceed light speed. I have found a support to my guess in https://en.wikipedia.org/wiki/Ellis_wormhole There parameter h which is angular...

Following your interest to find more profound idea in quantum mechanics, Heisenberg and Dirac observed that Poissson Bracket {A,B} which appears in analytic mechanics, especially in Hamilton's equation of motion ( https://en.wikipedia.org/wiki/Poisson_bracket ) has its quantum version $$...

Thogh I am a poor layman in GR, I am interested in understanding the question. Initial position and magnitude of initial velocity of the test body given, all we can arrange is the direction of the initial velocity. By that arrangement the test bddy could or couldn't pass the neck of worm hole...

Formula in ( ) , I referred as F, has v^2 only, no single v. Try replacing v^2 with x in my proposal. The equation would become easier to handle.