Recent content by aNxello
-
MHB Current Through A half-wave rectifier
So guys, I'm still lost, for the second part tho I found the answer,, I just have to do a full Fourier series of |sinx|, but for the first time I'm still confused if I should use the half range form or the regular form, and if I have o use the half range, how do I apply it to a function in the...- aNxello
- Post #8
- Forum: General Math
-
MHB Current Through A half-wave rectifier
Let me try this, I will update with my results, thank you! Also the range was already from 0 to Pi/Omega!- aNxello
- Post #6
- Forum: General Math
-
MHB Current Through A half-wave rectifier
This is a picture of my work, but if you can't read it I got $$a_{0} = \frac{4 \omega A}{\pi }$$ $$a_{n} = 0 $$ $$b_{n} = 4n^{2} \int \sin(\omega t)\sin(2nt\omega ) $$ And then that integral keeps repeating :/ (any tips on how to deal with partial integrals that repeat like btw?) thank you!- aNxello
- Post #3
- Forum: General Math
-
MHB Current Through A half-wave rectifier
Hello! So I'm stuck in yet another problem, I've been going through some Fourier Series problems (including one that I already asked about around here, and go great help!) and I've managed to get past most, but I got once again stuck on one. So for this one we got an alternating current of the...- aNxello
- Thread
- Current Rectifier
- Replies: 8
- Forum: General Math
-
MHB Fourier Series Involving Hyperbolic Functions
I think that 2 on top of the Pi was there because he had changed the range of the integral, so if we put it back to the original range the 2 shouldn't be there...I might be wrong tho And thanks! I'm new with latex and I was kinda learning as I was going along, I appreciate the tips! -
MHB Fourier Series Involving Hyperbolic Functions
So do you you mean like this? $$B_{n} = \frac{1}{\pi }\int_{-\pi }^{\pi} Cosh(ax)sin(nx)$$ -
MHB Fourier Series Involving Hyperbolic Functions
Woah! Thank you! I don't know what to say, you guys have helped me so much! I changed the title of the thread so it shows that it's solved (that's the right thing to do right?) I don't know how to thank you, you guys are awesome! (Bow) I had not realized Cosh(ax)sin(kx) was odd, that helped a lot! -
MHB Fourier Series Involving Hyperbolic Functions
Thank you very much, let me try to finish this, and I'll let you guys know how it goes! (Dance) -
MHB Fourier Series Involving Hyperbolic Functions
So for the first coefficient I got this $$a_{0} = \frac{e^{a\pi } - e^{-a\pi }}{\pi a}$$ but for the second one I keep looping while trying to do integration by parts (I keep getting back to the same integral over and over) Any clue on how to deal with this: $$a_{n} =\frac{1}{\pi } \int... -
MHB Fourier Series Involving Hyperbolic Functions
Ahh! Thank you, I had thought of using this, but I didn't know if it worked when x was next to some constant. Do you think it would be better to first integrate to obtain 1/a Sinh(ax)? I feel like replacing first will make it harder to find some of the coefficients. Anyways I'll try it out and... -
MHB Fourier Series Involving Hyperbolic Functions
[SOLVED] Fourier Series Involving Hyperbolic Functions Hello everyone! Sorry if this isn't the appropriate board, but I couldn't think of which board would be more appropriate. I was running through some problems I have to do as practice for a test and I got stuck on one I'm 99% sure they'll...