Recent content by APcalchelp

I'm not clear on what you mean by that. I understand factoring out the x^4 from the 5x^4 but not the 2x.

The Limx-->infinity of the function Square rt(5x^4+2x) / (x^2) Note* The square root is only in the numerator for the expression (5x^4+2x) I have tried multiplying by the complex conjugate but I am not sure if this is the correct way to do it. I did sqrt(5x^4-2x) over itself and got...