Solving the limit of a function with no calculator

Click For Summary

Homework Help Overview

The discussion revolves around evaluating the limit of a function as x approaches infinity, specifically the limit of the expression involving a square root in the numerator and a polynomial in the denominator.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss attempts to manipulate the expression, including multiplying by the complex conjugate and factoring terms. Questions arise regarding the correct method to factor out terms from the square root and how to handle the limit evaluation.

Discussion Status

Some participants have offered guidance on factoring terms to simplify the limit evaluation. There is ongoing clarification about the steps involved, particularly regarding the treatment of the term 2x when factoring.

Contextual Notes

Participants are working within the constraints of not using a calculator and are seeking to understand the proper algebraic manipulations needed to evaluate the limit correctly.

APcalchelp
Messages
2
Reaction score
0
The Limx-->infinity of the function Square rt(5x^4+2x) / (x^2)

Note* The square root is only in the numerator for the expression (5x^4+2x)



I have tried multiplying by the complex conjugate but I am not sure if this is the correct way to do it.

I did sqrt(5x^4-2x) over itself and got sqrt 25x^8-4x / x^2

I had that as my answer, but my teacher told me this was incorrect. If anyone could help and explain that would be great! Thanks a lot!
 
Physics news on Phys.org
APcalchelp said:
The Limx-->infinity of the function Square rt(5x^4+2x) / (x^2)

Note* The square root is only in the numerator for the expression (5x^4+2x)



I have tried multiplying by the complex conjugate but I am not sure if this is the correct way to do it.

I did sqrt(5x^4-2x) over itself and got sqrt 25x^8-4x / x^2

I had that as my answer, but my teacher told me this was incorrect. If anyone could help and explain that would be great! Thanks a lot!

Factor x4 out of both terms inside the radical, and bring this out as x2. You should be able to evaluate the limit then.
 
Mark44 said:
Factor x4 out of both terms inside the radical, and bring this out as x2. You should be able to evaluate the limit then.

I'm not clear on what you mean by that. I understand factoring out the x^4 from the 5x^4 but not the 2x.
 
APcalchelp said:
I'm not clear on what you mean by that. I understand factoring out the x^4 from the 5x^4 but not the 2x.

If you factor out x^4 from 2x, you are left with 2/x^3.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 16 ·
Replies
16
Views
3K
Replies
4
Views
2K
  • · Replies 31 ·
2
Replies
31
Views
3K
  • · Replies 105 ·
4
Replies
105
Views
11K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K
Replies
5
Views
2K