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_{x-->infinity}of the function Square rt(5x^4+2x) / (x^2)

Note* The square root is only in the numerator for the expression (5x^4+2x)

I have tried multiplying by the complex conjugate but I am not sure if this is the correct way to do it.

I did sqrt(5x^4-2x) over itself and got sqrt 25x^8-4x / x^2

I had that as my answer, but my teacher told me this was incorrect. If anyone could help and explain that would be great! Thanks a lot!