Recent content by araz1
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MHB Finding z-(1/z) Given z=r(cosx+isinx)
Yes there must be an error. Thank you for that.- araz1
- Post #7
- Forum: Linear and Abstract Algebra
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MHB Finding z-(1/z) Given z=r(cosx+isinx)
Your example makes sense, but that is a question in a book. Does it matter that z is in polar form?- araz1
- Post #5
- Forum: Linear and Abstract Algebra
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MHB Finding z-(1/z) Given z=r(cosx+isinx)
No it is not z minus its conjugate. it is z minus (1 over z).- araz1
- Post #3
- Forum: Linear and Abstract Algebra
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MHB Finding z-(1/z) Given z=r(cosx+isinx)
Hi Show that z-(1/z)=i2rsinx, given z=r(cosx+isinx) Thanks.- araz1
- Thread
- Replies: 6
- Forum: Linear and Abstract Algebra
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MHB Integrate 3/(x(2-sqrt(x))) - No Partial Fractions
Thank you for your time. -
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MHB Integrate 3/(x(2-sqrt(x))) - No Partial Fractions
Thank you for your time. -
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MHB Integrate 3/(x(2-sqrt(x))) - No Partial Fractions
integral of 3/(x(2-sqrt(x))) using u=sqrt(x)? But not using partial fractions -
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MHB Calculating New Emission Rate of Radioactive Source
Thank you Klaas. Did you use guess and check or numerical methods to get 0.824? Regards- araz1
- Post #3
- Forum: Set Theory, Logic, Probability, Statistics
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MHB Calculating New Emission Rate of Radioactive Source
A radioactive source emits particles at an average rate of 1 pe second. Assume that the number of emissions follows a Poisson distribution. The emission rate changes such that the probability of 0 or 1 emission in 4 seconds becomes 0.8. What is the new rate? Thanks.- araz1
- Thread
- Emission Radioactive Rate Source
- Replies: 3
- Forum: Set Theory, Logic, Probability, Statistics