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araz1
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integral of 3/(x(2-sqrt(x))) using u=sqrt(x)?
But not using partial fractions
But not using partial fractions
araz said:integral of 3/(x(2-sqrt(x))) using u=sqrt(x)?
But not using partial fractions
Thank you for your time.topsquark said:\(\displaystyle \int \dfrac{3}{x(2 - \sqrt{x} )} ~ dx = \int \dfrac{3}{u^2 (2- u)} ~ 2u ~du = \int \dfrac{6}{u (2 - u)} ~du\)
Let's pull a trick that occasionally works. I'm going to let 2 - u = a - v and u = a + v. If we add these two equations we get 2 = 2a. Thus a = 1. So 2 - u = 1 - v and u = 1 + v. Putting this into your integral gives
\(\displaystyle \int \dfrac{6}{u (2 - u)} ~ du = \int \dfrac{6}{(1 + v)(1 - v)} ~ dv = \int \dfrac{6}{1 - v^2} ~ dv\)
which you should be able to calculate directly. (Unless you know the trick to integrate this it is going to be difficult.)
-Dan
Thank you for your time.skeeter said:$u = \sqrt{x} \implies du = \dfrac{dx}{2\sqrt{x}}$
$\displaystyle 3 \int \dfrac{dx}{x(2-\sqrt{x})} = 2 \cdot 3\int \dfrac{dx}{2\sqrt{x}(2\sqrt{x} - x)}$
substitute ...
$\displaystyle 6\int \dfrac{du}{2u - u^2} = -6 \int \dfrac{du}{(u^2 - 2u + 1) - 1} = -6 \int \dfrac{du}{(u-1)^2 - 1}$
since partial fractions is off the table, the antiderivative will involve an inverse hyperbolic trig function
The general process for integrating this function is to first rewrite it as a sum of simpler fractions using the decomposition method. Then, use the substitution method to change the variable in the integral to make it easier to solve. Finally, integrate each term separately and combine the results to get the final solution.
The decomposition method involves breaking down a complex fraction into simpler fractions. In the case of 3/(x(2-sqrt(x))), we can rewrite it as 3/(x(2-sqrt(x))) = A/x + B/(2-sqrt(x)), where A and B are constants. This helps in integrating the function because it allows us to split the integral into smaller, more manageable parts.
Substitution allows us to change the variable in the integral to make it easier to solve. In the case of 3/(x(2-sqrt(x))), we can use the substitution u = 2-sqrt(x) to change the variable from x to u. This simplifies the integral and makes it easier to integrate each term separately.
The steps for using the substitution method in this integral are as follows: 1) Identify a suitable substitution, 2) Rewrite the integral in terms of the new variable, 3) Calculate the derivative of the new variable, 4) Substitute the new variable and its derivative into the integral, 5) Integrate each term separately, and 6) Substitute the original variable back into the solution.
No, using partial fractions is the most efficient and straightforward way to solve this integral. Other methods may involve more complex algebraic manipulations and may not always work for all integrals. The decomposition and substitution method used in this approach is the most efficient and reliable way to solve this integral.