Hi,
Thanks for all the advice, complicated subject isn't it.8-((
I will look up the links and see what I can learn.
The connection to the motor will be via a 2.5" throw crank to the motor shaft.
Good point about the leakage rate.8-))
Arnak
Hi Jbriggs,
Thanks for the input.8-))
So by my calculations :-
W = 0.00001*(101325 - 84088) + 0.00001 * 84088 * ln(84088/101325)
W = 0.87020288682 Joules.
Please excuse my lack of knowledge of algebra but is the component ln the designation for the result of (Pnew/Pamb)?
I have converted...
Hi,
Thanks for that formula.9-))
What units would the work be in please?
Am I right in saying then that with a cylinder of 200 x 50mm V= 10000 mm3
Pressure difference = 2.5psi
So 10000 x 2.5 = 25000 units?Arnak
Hi,
Can someone give me some guidance on how to calculate the work or energy required to create a vacuum.
For example, I would like to create a 2.5psi vacuum in a tube of a specific length and diameter using a pneumatic cylinder to remove the air.
How would I go about calculating the...
Hi Folks,
Could someone please help me?:blushing:
I want to work out the power requirements for the torque or wattage required in an electric motor when evacuating a vacuum to a certain level.
The tube to be evacuated is 200 mm x 50 mm and the evacuation would be done using a pneumatic...