Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

How to Calculate Work to produce a Vacuum?

  1. Jan 13, 2014 #1
    Hi Folks,

    Could someone please help me?:blushing:

    I want to work out the power requirements for the torque or wattage required in an electric motor when evacuating a vacuum to a certain level.

    The tube to be evacuated is 200 mm x 50 mm and the evacuation would be done using a pneumatic cylinder of 50 mm bore and 50 mm stroke.

    The vacuum to be achieved and maintained is 2.5 psi or 5" Hg.

    The pneumatic cylinder will be driven by an electric motor but how to calculate the motor requirements?

    To keep it simple I will ignore losses due to friction etc.

    Could someone could please help me with the formula to work that out?:confused:

    Thanks,

    Arnak
     
  2. jcsd
  3. Jan 13, 2014 #2

    Simon Bridge

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member
    2016 Award

    It's the same as the work required to reduce pressure.
    Opposite of the work required to generate the pressure.

    Depends a great deal on how the pressure is being changed.
    It will not be easy to model from first principles - you should probably just look it up.

    See how other people solve the same problems.
    http://www.gastmfg.com/vphb/vphb_s4.pdf [Broken]
    http://lpc1.clpccd.cc.ca.us/lpc/tswain/chapt3.pdf
     
    Last edited by a moderator: May 6, 2017
  4. Jan 14, 2014 #3

    Baluncore

    User Avatar
    Science Advisor

    I believe the cylinder rod area is unimportant if the rod end of the cylinder is open to atmospheric pressure. The 50mm pump cylinder will have 2.5 psi on one face and 14.5 psi atmospheric on the other. That makes a differential pressure of 12 psi. The area of a 50mm piston is about Pi square inches so you need to apply a force of Pi *12 psi = 37.7 pounds force to the rod.

    Torque cannot yet be calculated because you have not explained how you will couple the rod to the motor.

    The ongoing cost of maintaining the 2.5 psi absolute pressure will be determined by the leakage rate you must make up.

    The motor power requirements will be decided by the time you have available to pull the initial partial vacuum.
    The rate of air removal must be faster than the leakage rate you need to make up.
     
  5. Jan 14, 2014 #4
    Hi,

    Thanks for all the advice, complicated subject isn't it.8-((

    I will look up the links and see what I can learn.

    The connection to the motor will be via a 2.5" throw crank to the motor shaft.

    Good point about the leakage rate.:cool:)

    Arnak
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook