Recent content by Aryan Andaleeb

Yes! Let, 7kg mass be m1. 3kg mass be m2 For m2, we can write $$ Fnet = Faction-reaction + Fapplied from right $$ $$ Or, 6 = Faction-reaction + (-4) $$ $$ Therefore, Faction-reaction =...

This way, it becomes that a = 2m.s^-2

For 1st law, it mathematically states, if Fnet = 0 on any object, then it continues in its state of motion or rest foreverFor 2nd law, F is proportional to rate of change of momentum (not only proportional, but also are equal. i.e. F =ma) For 3rd law, If A applies force F on B, B applies...

Yes.

Yes

Well I don't find a particular equation. It's just that I found out all the forces that can be acting using free-body diagram. And I made sum of forces

The floor is friction less. and the boxes were at rest prior to force application. That's all.

Homework Statement 1) Are F and F' as shown in figure, the action-reaction forces between the two boxes? 2) What is the action and reaction force between the two boxes? Homework EquationsThe Attempt at a Solution I think F = 28N and F' = - 28 N Simply adding the action- reaction forces for...

What do you mean here?

Okay, I agree with you. But, now, isn't this true as well? I1 = V1 × Z [Where, Z means electrical impedance in the primary coil, generated by the a.c. generator]

That's alright. But how is the primary current determined in a transformer? And thanks a lot for your help.

Homework Statement If we denote: Alternating current in the primary coil as I1 Alternating current in the secondary coil as I2 Similarly, we denote, Number of turns in primary coil as N1 Number of turns in secondary coil as N2 And, we denote, Voltage generated across primary coil as V1...

Hello, everyone! I'm Aryan Andaleeb Azim, and I'm a 9th-grade school student. Feeling really happy to join a new forum, and I hope that I'll have a great time in learning and sharing problems on physics with all over here. I would really like to get introduced with new friends here gradually...