duh! Thinking too hard is what I do. I think.
(I was fooled because I was following copying the steps of a related proof on the same page...)
otherwise proof ok?
thanks tads for the reply...much obliged!
Homework Statement
If G is a finite simple group and
H is a subgroup of prime index p
Then
1. p is the largest prime divisor of \left|G\right| (the order of G)
2. p2 doesn't divide \left|G\right|
I think I have this proved, but want to confirm my reasoning is sound.
this problem is...