Recent content by asllearner

duh! Thinking too hard is what I do. I think. (I was fooled because I was following copying the steps of a related proof on the same page...) otherwise proof ok? thanks tads for the reply...much obliged!

Homework Statement If G is a finite simple group and H is a subgroup of prime index p Then 1. p is the largest prime divisor of \left|G\right| (the order of G) 2. p2 doesn't divide \left|G\right| I think I have this proved, but want to confirm my reasoning is sound. this problem is...