Recent content by asz304

Thanks. I knew I'll mess something up with the denominator because of "-q2" and q2 = 1.85*10^-6 C.

@ Abhishekdas Wow..both of our answers were right. The computer is the only thing that's not doing its job :wink:. For the answer, instead of 1.83*10^-1 Nm^2/C or 1.831*10^-1 Nm^2/C, I used 0.183 Nm^2/C and the computer accepted it. Thanks guys EDIT: Just to make sure I understand...

k I got it. So if I were to get the flux of the right side of the cube it would be independent from x and z? and if I took the flux in the front of the cube it would be independent from y and z? or would it just be equal to 0 since E(x,y,z) = Kz j + Ky k?

I didn't get this part:

I had that answer before, but the computer still tells me that it's the wrong answer.

Oh. I think I know why my integral expression is wrong, it's because I forgot to put dA, dA = k dx dy. And I know that the only component that contributes the flux of the top surface is z.

@ Abhishekdas Yeah, I tried to input the number and the computer said I gave it the wrong answer, with 3 tries left.

How is my integral expression in b) wrong?

\int EA = \int Ea^2 = Ea^3/3? = ka^4/3

EDIT: integral from b to a where b is 0 and a is 0.440 m.

I came with a second answer of 0.0403 m x(2) = -q1d/(-q1-q2) but the computer says I'm giving it the wrong answer. Is there something that I'm doing wrong?

This is what I did but I still get the wrong answers... a)\int EA = \int (ka)(a^2) = k*a^3/3 = 1.22*10^-1 Nm^2/C b)\int EA = \int(ka)(a^2) = k*a^3/2 = 1.83*10^-1 Nm^2/C What am I missing here?

Homework Statement A 2.96 uC and a -1.85 uC charge are placed 4.48 cm apart. At what points along the line joining them is the potential zero? Let V = 0 at r = infinity and enter the smaller distance first. Homework Equations V = k*q/r The Attempt at a Solution V(total) = 0 =...

E(top) = Kz j Is this right? I tried substituting the values for that, and I tried something different for getting the integral of E(top) but still got the wrong answers for both tries.

Thats what I answered on my first try, but it turned out to be wrong. @ Abhishekdas I tried your answer but it doesn't work. How did you do it anyway?