Recent content by Aurelius120

You mean this video? Here he says that if the collector circuit is open, all emitter current will flow through base and transistor will burn. But If there is no collector current, then why will there be any amplification, the only current should be the small base current which flows through...

So in this video he said that no matter how powerful a battery you apply across the N and N of the transistors, current will not flow unless a second battery is used across N and P because there is a depletion zone at one NP junction. But the P-region of NPN is very thin so can't the charge...

I was reading about transistors. There was one good video.. It said to treat the NPN transistor as two diodes. And so I did. I remember learning that a forward biased diode can be treated as a cell that causes a potential drop equal to the barrier potential (while a reverse biased diode is an...

Oops. Yes this was my mistake. The second diagram I drew as the source of error like you were saying.

Was he trying to say something different than the pictures I posted? I think I have made a mistake.

What I meant is that I have to blow against atmospheric pressure but But here I have to blow against water pressure. I think I am making a mistake but I can't figure it. Sorry for the late reply.

The Then as long as water level is at the level of upper rim of the bell or lower, we have to blow against atmospheric pressure since downwards pressure of water is zero. So the amount of exhaled air is same in 400mL or 0mL. Problem will be if water level is above bell at 0mL. Because of...

Upthrust exerted by water on the bell (including the air trapped within,right) because that's the volume displaced.

So if some air already exists for example at 400mL, it will be easier to blow into it (than doing so at 0mL) because there is more buoyancy?

I meant this. (Water level at level of bell and bell resting on air pipe) Since normal reaction is balancing the bell. We have to blow against (weight-buoyancy), Right? Similar to if we had to lift/move a metal block with only force of exhaled air?

So it will be like trying to blow away a chunk of solid metal? 😯😲

But if it is at zero when the bell is resting at the water level,bell can't sink any further? Blowing air into it will still make it float, and give the required reading right?

Why would it be unreliable? Because we have to blow air against mass of bell which would make it difficult to exhale all air?? I think to make the net force zero on the bell?

So hypothetically if the bell rests on the mouth of the inner metallic pipe, the water won't form a proper seal? Why so? Is it because we will be blowing air into the water?

In the theory, it was asked to set it at 400-500 mL and do the experiment. In the practical lab, teacher asked us to lift it to 400-500mL and rotate the pointer to zero 😅