How does a transistor act as an amplifier?

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Transistors, specifically NPN types, function as amplifiers by utilizing their structure, which includes a thin base region shared between two diodes. The amplification occurs because the collector current is a multiple of the base current, rather than a simple addition, due to the transistor's ability to control a larger current with a smaller one. A depletion zone at the NP junction prevents current flow unless a sufficient voltage is applied across the base-emitter junction. Understanding the transistor's operation requires more than just the diode model; resources like Khan Academy and Wikipedia provide detailed explanations. Overall, grasping these concepts is essential for comprehending how transistors amplify signals effectively.
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Homework Statement
How does a transistor work?
What is the explanation for amplification of current?
Relevant Equations
NA
I was reading about transistors. There was one good video.. It said to treat the NPN transistor as two diodes.
1000000174.jpg

And so I did. I remember learning that a forward biased diode can be treated as a cell that causes a potential drop equal to the barrier potential (while a reverse biased diode is an open circuit?)
1000000173.jpg

But I don't know how to proceed further?

And the video explained how the current is amplified a little too fast towards the end. I didn't understand it. From the circuit diagram and the explanation in the video I can somewhat see that the current will be increased. But I don't understand how? And definitely don't see how it increases by multiplication instead of addition?(Like why is the collector current something times the base current and not something plus the base current?)
 
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Sorry, I didn't watch that video. Transistors are a bit more complex than just two separate diodes as you've drawn in your schematic. The key point is that they share a very thin base region, so it's a single combined device. Honestly, there is a ton of information on the web explaining them. You'll do better to study a bit more than have me give a worse explanation than what's already out there. I would start here:

https://www.khanacademy.org/science...r-working-class-12-india-physics-khan-academy
 
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DaveE said:
Sorry, I didn't watch that video. Transistors are a bit more complex than just two separate diodes as you've drawn in your schematic. The key point is that they share a very thin base region, so it's a single combined device. Honestly, there is a ton of information on the web explaining them. You'll do better to study a bit more than have me give a worse explanation that what's already out there. I would start here:

https://www.khanacademy.org/science...r-working-class-12-india-physics-khan-academy
So in this video he said that no matter how powerful a battery you apply across the N and N of the transistors, current will not flow unless a second battery is used across N and P because there is a depletion zone at one NP junction.

But the P-region of NPN is very thin so can't the charge carriers simply cross it when the applied voltage is large enough.

Also why is the ratio of the currents preserved? Why is it only dependent on the smaller voltage?
 
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Aurelius120 said:
But the P-region of NPN is very thin so can't the charge carriers simply cross it when the applied voltage is large enough.
Sure. That is known as "letting the smoke out" of the transistor. Search on BVceo
 
berkeman said:
Sure. That is known as "letting the smoke out" of the transistor. Search on BVceo
You mean this video?
Here he says that if the collector circuit is open, all emitter current will flow through base and transistor will burn. But
If there is no collector current, then why will there be any amplification, the only current should be the small base current which flows through the emitter as well.
Why will attaching an open battery across the NN ends cause any effect on the circuit?
 
Aurelius120 said:
You mean this video?
Here he says that if the collector circuit is open, all emitter current will flow through base and transistor will burn. But
If there is no collector current, then why will there be any amplification, the only current should be the small base current which flows through the emitter as well.
Why will attaching an open battery across the NN ends cause any effect on the circuit?
Much like @DaveE I don't generally watch YouTube videos as references. If you have access to the Khan Academy, you can view their instruction video on transistors that Dave linked to. You can also read the Wikipedia article, especially the section on Simplified Operation:

https://en.wikipedia.org/wiki/Transistor

For me, one of the best images to keep in mind when thinking about how an NPN bipolar transistor works in the "Common Emitter" current amplifying configuration is using this graph:

1742757520950.png

https://www.electronics-tutorials.ws/transistor/tran_2.html

That is also a good tutorial to read through to understand why that plot is so instructive.
 
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