Recent content by aznmaverick

ook, sounds good, thanks so much!

how did u get the answer\alpha\sigma/\epsilon0?? for a infinite line charge its just E= \lambda/2\pi\epsilon0\alpha for one of the cylinders rite? and then if we apply the superposition principle we get \alpha\sigma/\epsilon0??

They are treated as infinite and the distance r is never inside the other cylinder. the distance of the cylinders apart from each other is d. And we want to find the total e-field at a point r (for r<d) The cylinders are non conducting cylinders well. Does this make more sense now?

Ok, so that would be the combined electric force at that point, r, away from the 1st cylinder?

Yes, we assume that L>>a (the radius of the cylinders). The one on the left has a (+sigma) density charge and the one on the left has a (-sigma) density charge. Hope this information helps!

2 Cylinders each of length, L, are separated by a distance d. Each has a radius, a. Use the principle of superposition to find the total electric field at a distance, r, from the 1st cylinder. What I know so far: For One cylinder Applying gauss law, i have E(2(\pi)(r)(L) = charge enclosed/...

Homework Statement Given a constant magnetic field, B, into the plane of the board, how much induced current flows through R and C. Homework Equations Induced EMF =-d/dt (Fluxb) Iind= Induced EMF/R V= dx/dt = constant (velocity of sliding conductor) Lenz Law The Attempt at a Solution

Got it, thanks!

Yea, 1 mole was a given. T is still not given. So does that mean there's no 'real answer' to this question w/o T given?

Yes, well, n=1 mole, and T is unknown, but we know that its a constant. So we cannot solve for it?

Yes, I got that from Q (from C to A) = Delta U (C to A) + W (C to A) and since Delta U (C to A) = 0, Q (C to A) = W ( C to A). W (C to A) for an isothermal process is = (Integral from C to A) P dv Using the formula PV = nRT and solving for P, we get P = nrT/V, so W (C to A) = (Integral from...

Homework Statement Calculate Q(in) and Q(out). Homework Equations Specific Heat: Cv = 5/2 R R = 8.314 J/mol K The Attempt at a Solution For the process C-> A, it is an isothermic process but we are not given temperature. The equation to finding the total work done from C->A is nRT...