i have a question that I cannot solve;
Show that the rms velocity of a sodium atom moving in a vacuum chamber at 300 kelvin is about 570 metres per second
pV=nRT and 3pV=Nm<c^2>
Define I(n) by I(n) = integral of x^n / square root(1+x^2) dx. Evaluate I(0), I(1) and then establish the reduction formula I(n) = ((root2)-(n-1)I(n-2))/(n) for suitable values of n, which should be stated
Here is my attempt
I found I(0) first,and got the answer to be...
1. integrate 1/(1+(xx-1)^0.5)
I.E. Integrate 1 over the sqaure root of( x^2 - 1)
2. I started by rationalizing the fraction and then i split the equation into two. I THEN let x = root2 (tanh(u)) for the 1/(xx-2) fraction, and have no idea what to do from there :S
1. The base of a cloud has an area of 2*10^7 metres squared and is on average 1km above the ground. treating the base of the cloud, the ground and the intervening air gap as a parallel plate capacitor, calculate the capacitance.[relative permittivity of air = 1.0]
2. I tried to say C...
I have a few questions:
1. 'small smoke particles in air are seen under a low magnification microscope to move randomly at a speed of 0.10mm/s. The speed of sound in air is 330m/s. Estimate the mass of the smoke particles.
I cannot make the link between speed of particle and speed of sound -...
Hello,
I have studied X-ray emission when an electron beam is fired at a tungsten target - But when I was presented with the graph of Intensity versus wavelength, I was confused...
I saw a curve, and on it there were spikes. What are these spikes, and why are they caused?
Something to...
Hi,
I have a question concerning a hydrogen spectrum:
There are 4 energy levels drawn:
Starting from the top
-1.4 * 10^-19 Joules
-2.4 * 10^-19 Joules
-5.4 * 10^-19 Joules
-21.8 * 10^19 Joules
1st question:
Going from the second level to the third from the top (from -2.4 to...
Yes, I have got the horizontal speed to be 3.5 metres per second
The vertical speed is 11.5 metres per second
But what trignometric function? I do not know of any which can predict the vertical entry angle of a perabola
Oh! That seems right - thank you very much!
One last question - how do you calculate 'the angle which the diver makes, to the vertical, upon entry to the water' ?
Thank You, again
Ah! That makes much more sense! Thank You
Finally, make I ask you - how could you calculate 'the angle which the diver makesm to the vertical, upon entry to the water?'
Ok, but he has water beneath him for all 8 metres.
The question does not say that he runs 6.5 metres and then falls, it says he travels 8 metres in the air...
So i am not sure