Recent content by bai_mi
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Calculate rest mass given relative speed and kinetic energy?
What do you get with E=γmc^2 then?- bai_mi
- Post #7
- Forum: Introductory Physics Homework Help
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Calculate rest mass given relative speed and kinetic energy?
20*10^9*1.602*10^-19= ((1/(root(1-0.5^2)))-1) m*(3*10^8)^2 m=2.30*10^-25 kg- bai_mi
- Post #5
- Forum: Introductory Physics Homework Help
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Calculate rest mass given relative speed and kinetic energy?
Sorry I meant that when I use E=γmc^2 (total energy formula), I get the correct answer. E=(γ-1)mc^2 (kinetic energy formula) gives the wrong answer. The question should be 20 GeV of total energy, right?- bai_mi
- Post #3
- Forum: Introductory Physics Homework Help
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Calculate rest mass given relative speed and kinetic energy?
The answer is 3.079*10^-26 kg I tried doing E=mc^2 20*10^9*1.602*10^-19=m*(3*10^8)^2 m=3.56*10^-26 kg However when I do E=γmc^2 I get the correct answer. Is the question wrong, because isn't it 20 GeV of kinetic energy, not total energy?- bai_mi
- Thread
- Energy Kinetic Kinetic energy Mass Relative Relative speed Rest Rest mass Speed
- Replies: 7
- Forum: Introductory Physics Homework Help