Recent content by balllla

Well I understand that -(Qloss)=Qgained and you need to get all variables to one side and other numbers on the other side, this is what i have done but I'm stuck -(Qloss)=Qgained -(Qloss silver)=Qgained of water=Qgainedofcalirmiter -(mcdeltat)=mcdeltat+mcdeltat...

I cannot formulate an expression for the given terms. I've completed algebra, adv. algebra and now I am precalc and I just can't figure out the algebra to complete this practice problem.

Homework Statement A .4lb piece of Hg at 210 F is placed in .3lb of water that has a temperature of 70.0f. The water is in .1lb brass calorimeter. What is the final temperature of the mixture? Homework Equations Q=MC(deltaT) The Attempt at a Solution The part that I'm...

Homework Statement A. A Volkswagen Rabbit has a mass of 1090 Kg and can go from 0mi/hour to 65 mi/hour in 12.0 seconds with an average acceleartion of 2.42 m/s^2. Disregarding friction, what force must the engine be producing? B. Disregarding friction, how much mass would need to be...

Homework Statement what force is required to give a projectile weighing -475 N an acceleration of 3.00x10^3m/s^2 Homework Equations f=ma The Attempt at a Solution f=ma -175 N=m (-9.81m/s^2) m=48.4 Kg f=ma f=(48.4kg)(3.00x10^3m/s^2) f=145000 N hi thanks so much for...

OK. My acceleration is approx. 360432600000000 m/s^2. When doing the algebra I get an answer of .00000001 seconds for time, but my online computer software is saying it is wrong, I know that my acceleration is right but how is my time wrong?!

vi=14200 m/s vf=3.73x10^6 m/s x=.0193m t=? a=?

would this work 3.73x10^6 ^2= 14200m/s^2 + 2a(.0193m) ? what would that give me, my acceleration? but I still don't know how to do the first part of the problem. many thanks.

ok but what actually am I trying to find. Am I trying to find time and are 14200m/s and 3.73 velocity?

LaTeX Code: v^2 = v_0^2 + 2 a \\Delta x Would I use this equation which would find out the acceleration to later find out the displacement.?

1. An electron in a crt accelerates from 14200 m/s to 3.73x10^6 m/s over 1.93 cm. how long does the electron take to travel this distance? and What is it's acceleration (in m/s^2) The supposedly "easiest" question on my physics worksheet has me stumped. I know that I have to convert so it would...