F=MA + Average Acceleration etc.

• balllla
In summary, to find the force produced by the engine of a Volkswagen Rabbit, disregarding friction, we use the equation f=ma where the mass is 1090 kg and the average acceleration is 2.42 m/s^2. To determine the amount of mass that would need to be removed from the car to achieve the same velocity change in a shorter amount of time, we use the same force found in part A but with a different acceleration of 2.90 m/s^2. This results in a new mass value, which when subtracted from the original mass of 1090 kg, gives us the amount of mass that must be removed.
balllla

Homework Statement

A. A Volkswagen Rabbit has a mass of 1090 Kg and can go from 0mi/hour to 65 mi/hour in 12.0 seconds with an average acceleartion of 2.42 m/s^2. Disregarding friction, what force must the engine be producing?

B.
Disregarding friction, how much mass would need to be removed from the car above if it were to make the same velocity change in only 10.0 seconds with an average acceleration of 2.90m/s^2.

f=ma

The Attempt at a Solution

a.f=ma
f=(1090 kg) (2.42m/s^2)
f=2640N

okay I get a but do not understand B. How can the average acceleration be 2.42 m/s^2 when 0mi/hr to 65 mi/hour in 12.0 seconds when it is actually 5.41 m/s^2. Help is needed in finishing the problem then...

thank you.

In part B you are going to use the force you found in part A, NOT the acceleration.
So if you have the same force, but less mass do you think the car can get up to the same speed in more or less time?

balllla said:

okay I get a but do not understand B. How can the average acceleration be 2.42 m/s^2 when 0mi/hr to 65 mi/hour in 12.0 seconds when it is actually 5.41 m/s^2. Help is needed in finishing the problem then...

65 mi/hr = 29 m/s

B.
F = 2640 N
a = 2.90 m/s^2
F = ma

Solve for m. This is the mass of the car after some of the original total mass had been removed. Subtract this mass from m = 1090kg

What is F=MA and how is it related to average acceleration?

F=MA is a fundamental equation in physics that describes the relationship between force, mass, and acceleration. It states that the force (F) applied to an object is equal to its mass (M) multiplied by its acceleration (A). This equation is closely related to average acceleration, which is the change in velocity over time.

How is F=MA used in real-world applications?

F=MA is used in many real-world applications, including engineering, transportation, and sports. For example, it is used in designing structures and machines to ensure they can withstand the forces they will experience. It is also used in calculating the performance of vehicles and athletes, such as calculating the force needed for a car to accelerate to a certain speed or the force exerted by a runner's legs.

What are some common misconceptions about F=MA?

One common misconception about F=MA is that it only applies to objects in motion. In reality, this equation can also be used to calculate the force needed to keep an object at rest. Another misconception is that F=MA only applies to linear motion. However, it can also be applied to rotational motion, as long as the mass and acceleration are considered in terms of their rotational equivalents.

What are the SI units for F=MA?

Force is measured in newtons (N), mass is measured in kilograms (kg), and acceleration is measured in meters per second squared (m/s²). Therefore, the SI units for F=MA are N·kg·m/s², which is equivalent to a newton (N).

How does F=MA relate to Newton's Laws of Motion?

F=MA is essentially a mathematical representation of Newton's Second Law of Motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. This law is one of the three laws of motion developed by Sir Isaac Newton, and it helps to explain the behavior of objects in motion.

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