Recent content by Barlock

It appears that the answer book i have says its 406, while the paper i got says 412. I guess someone done it wrong on paper, but the book must be correct so its 406. When i do the midpoint thing i get the equation V=x-75 and y being the shortest distance to wall is (x^2-75^2)^1/2 which gives me...

Could you perhaps make some sorth of a drawing or a picture on how this represents the problem?

What do you mean at the midpoint between the men? I think that the sound wave as it leaves the gun expands and hits the wall echoing back first again heard by guy who fired the gun as the circle of sound goes straight from gim to wall and back and the other catches the vibration only when the...

Its 402 not 412 sorry, i rounded up wrong but the book tells its 412, so i guess they got it wrong.

I get the answer 412, which is correct.

Im sure the equation V=((x-150)+(150^2+x^2)^1:2)/2 accuretly describes the problem if its ment that 2 sec is the time between shots and 1.56 if its total time from begg of shot 1 to end of echo.

I have the same equation as you do but with a denominator being 2 rather than (2-0.44). I took it as 2 seconds between the shots. The answer book gives is 406 and i get 410.

It travels for another 1.56 second the distance x + (x-V*0.44) right?

I got closer to the answer by writing that V*1.56=2x-V*0.44 but i get 340m which is less than true answer. My logic is this. It takes 0.44 s to get to guy 2 and by that time sound has traveled distance V*0.44 along x side of triangle whose base is 150 m. And third side is x...

Homework Statement The human beings are standing at equal distances from a big and high wall. Distance between them is 150 m. When one fires the gun the other hears two shots in an interval of 2 seconds, using the speed of sound to be 340.298 m/s calculate their distance to the wall. Homework...