Recent content by BatmanACC

Hey mate, I don't have time to run over the specifics right now (studying for my own exams!) but here's how this is done. Edit...I just told you how to calculate the mass of a wire LOL wow it's getting late, let me re-do this Okay note that the intersection of these curves happens at y=x...

In the equation that you stated it seems that you require Mass. I didn't see any listed. Perhaps you had the mass cancel out but I don't see that. Correct me if I'm wrong. But if you have the mass (assuming you just didn't post it) Than it would be easier to equate PE and KE Find the potential...

Hold the phone. You know the starting height and the height at the edge of the roof. The difference between them is your vertical component of your triangle. The difference is 5m (12-7). We have a right angled triangle with a 30 degree angle to the horizontal. Meaning sin30=5/h and h=5/sin30...

7m = 2.5 x T + 4.9T^2 4.5T^2 + 2.5T - 7 = ) -2.5 square root ( 2.5^2 -(4)(4.9)(-7)) / 9.8 -2.5 +or- 12 / 9.8 X1= .969 X2= Negative

Sorry, my mistake. I forgot to add in you must decompose your Ff as well. Since FF is going down the slope you decompose it into vertical and horizontal values. Do the exact same for your Fn (Get Fn Via decomposing your FG). Take the Horizontal component of FF So Fn(H) - FF(h) = MV^2/R if the...

No 2.5 is the vertical component. Use sin/cos/tan. You have 5m/s vector at 30 degrees to the horizontal. Thus decomposing it means. 5sin30 = vertical. Use that value (2.5) in the equation D= v1 * Time + 1.5(a)t^2 It'll come out to your answer. I already checked it twice for you.

I never actually did the question. But that's the solution set if the Ff is keeping the car from skidding outside. If by sliding the question means sliding down the ramp than the Fnet= Fn(H) H= horizontal - Ff = MV^2/R. Try that.

Hey there. You are going about it the wrong way. You need to decompose your vector into vertical and horizontal components. After decomposing you should find your vertical component is 2.5m/s. This is your V1. Now we analyze vertically. We use the equation D= V1 * T + .5(A)T^2 We have D...

Assuming by sliding the question means skidding outside the circle (if its the opposite simply reverse what I am about to show you) this is how you'd go about itWe know Fnet=MAc What we also know is that MAc is comprised of every vector in the direction of the center. Meaning you must decompose...

Homework Statement If you were on a spaceship moving away from Earth at .8C, would you observe any change in your shoe size, mass, or your pulse? Would an observer from Earth note any change in these quantities? Homework Equations L = Lo[sqrroot(1-v2/c2)] M = Mo/ sqrroot(1-v2/c2)The Attempt...

Thanks guys. My solution set is similar to both of yours. I used 2T= To/sqreroot(1-v2/c2) and 2T = To/x where x=.5 This yields sqreroot(1-v2/c2) = .5 Through squaring both sides and moving the variables/numbers around you obtain .75c2=v2 Simply square root that to get the answer which is...

Thanks for taking a look. The following question is that is that from a grade 12 academic physics course. Homework Statement Scientist Ludwig von Drake, while in his laboratory, measures the half-life of some radioactive material which is in a bomb, approaching with speed v. Donald Duck, who...

If it starts from rest you know: - V1=0 - V2=? - Displacement=12m - Time=3s To get V2 we use the equation that relates all our known variables. This equation is; Delta D={(v1+v2)/2}* Delta Time After you find V2 use the equation A= (V2-V1)/Delta Time to find acceleration. From there plug A...