Recent content by bbd001

P = ρgh h = P/ρg = 3121 Pa / (997 kg/m³ * 9.8) = 0.32m So the pressure from the 10Kg can only push the X, 0.32m upward instead of 127.48m. Is that correct?

F = ma = 10kg * 9.8 = 98N P = F/A = 98/(3.14 * 0.1 * 0.1) = 3121 Pascals

Someone told me the "extra" water weight inside the pipe will be equal to the weight of the 10kg object. (it seems make sense) 10kg = 0.01 cubic meters of water. Using Vol to cal the cylinder height: X = 127.48m Y = 0.32m Is that correct?

NO TEMPLATE BECAUSE ORIGIONALLY SUBMIIED TO NON-homework forumHi, I have a pipe connects to a container's outlet. The container contains water and the pipe is open-ended. When a 10Kg object is placed inside the container and compress the water. Can you tell me how to calculate the displacement...

thx for the reply russ. Can you give me more information? If I have a tank fill with helium, it is part of the system. Releasing the gas from the tank is like cutting some of the balloons. If I want to move up again, the system cannot get extra helium back from the sky. If I...

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