I have tried to put x+1 = x^2+bx+c when x=1 and x=3
I get the result of b = -3 & C =4
I just confuse the part of| x-2|>=1 , what is that mean in this question?
Homework Statement
Determine the value of b and c such that the function is continuous on the entire real number line
Homework Equations
f(x) = { x+1 , 1<x<3
x^2+bx+c, |x-2| >=1
The Attempt at a Solution
What is the best way to get the b and c value?[/B]