Recent content by BCox

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    Can the Difference of Two Hypergeometric Functions be Expressed as One Term?

    We have the property such as this Hypergeometric2F1[a,b,c,z] = (1-z)^(c-b-a)*Hypergeometric2F1[c-a,c-b,c,z] If we wanted to keep the 2nd term of the hypergeometric function constant, what would the r.h.s. be? Hypergeometric2F1[a,b,c,z] = something *...
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    Can the Difference of Two Hypergeometric Functions be Expressed as One Term?

    Thank you for checking in Maple. Hmmm... two things 1. Mathematica software sometimes gives erroneous analytic solutions for integration. Do we fall into that kind of error w. Maple sometimes? 2. If the above is analytically correct, can we represent the solution as exponential or trig...
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    Can the Difference of Two Hypergeometric Functions be Expressed as One Term?

    Hello: I need to simplify the following if possible _2F_1(a,b;c;-x^2) - _2F_1(a+1,b+1;c+1;-x^2) In fact, a= 1/2 and c=3/2 and b>=1. In other words, the difference above that I am interested in is more specifically _2F_1(.5, b; 1.5; -x^2) - _2F_1(.5+1, b+1...
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    How to Specify an Interval in Mathematica for the Integrate Function?

    Yes, exactly. L pertains to the integrand.
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    MATLAB Plotting a 3D Function in Matlab: Visualizing the Evolution of a System

    Hello: I would like to generate a similar 3D graph in MATLAB. The points are (x,y,z). I would like to have a SCATTER plot on the (x,y) axes. But then each one of these (x,y) points are LINE connected to their respective z point. If anyone has code for this, or know how to do this in SAS...
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    How to Specify an Interval in Mathematica for the Integrate Function?

    Hello: I would like to use Mathematica Integrate function. But how do I specify the following interval (0 , Pi/2 ] ? When I write L \[Element] (0, Pi/2] It simply bolds ( and ] in orange in error. How do I get Mathematica to recognize that for the integrand, my value L is...
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    Exploring Associated Legendre Functions: Applications and Uses

    ok. In what time of application or simply why would we multiply Associated Legendre with another function and then integrate over the real line?
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    Exploring Associated Legendre Functions: Applications and Uses

    Hello: What are Associated Legendre functions? What are they good for in terms of applications?
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    Rate of lim exp(x) ~? rate of lim exp(-x)

    Yes, I looked at that more closely and realized that is wrong. The question behind the question is, what is the rate of the following at which the function below approaches zero: lim (1/y) arccot [ -exp(x)/sin(y) - cot(y) ] ->0 as x->infinity where y is (-pi,0)
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    Rate of lim exp(x) ~? rate of lim exp(-x)

    Yes, it does. What if my f(x) = e^x + cot y ... where my y is another variable for which cot y may diverge to positive infinity? I am still only interested in the rate for when x -> infinity. What would g(x) look like for the rate at which the new f(x) approaches infinity at the same...
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    Rate of lim exp(x) ~? rate of lim exp(-x)

    Hello: The actual functional analysis for my rate of convergence is a bit more complicated. But essentially the problem I have is knowing if the following is true: lim exp(x) -> infinity as x->infinity is at the same rate as lim exp(-x) -> 0 as x-> infinity ? Would really appreciate...
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    To find logarithm of a complex number

    Perhaps this may be correct... 1. arcot = ( pi/2 - arctan() ) 2. lim 1/d * [ pi/2 - arctan() ] as x->infin 3. We know that the express above goes to zero. We just want to know how fast. So lim 1/d * [ pi/2 - arctan() ] = 0 as x->infin 4. 1/d * arctan[ - exp(cx) / sin(d) ]...
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    To find logarithm of a complex number

    right. It's tricky
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    To find logarithm of a complex number

    Hmm... perhaps a rephrase of the question is more appropriate. I want to take the limit of the following function as x -> infinity (1/d) * arcot [ - exp(cx) / sin(d) ] where d is (-pi,0) Now a prior condition would stipulate that the above has to go to zero as x tends to infinity...
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    To find logarithm of a complex number

    Hello: So if my function was LN [ -exp(cx)/sin(d) - i ] = ? Then, I would decompose it to real and imaginary parts? The larger problem is LN [ -exp(cx)/sin(d) - i ] - LN [ -exp(cx)/sin(d) + i ] where c and d are constants. ?
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