I entered 57.3 for part a and the answer was still wrong. I got -50.3°. Perhaps my calculations are wrong...do the equations look correct to you?
This is how I calculated the angle:
tanθ=Ry/Rx
tan−1(inverse tan)(Ry/Rx)
We're subtracting because that's the homework question as it was written by the instructor. I added this course late and do not know how to add vectors. I've ordered the textbook, but it hasn't arrived yet.
Hi rl.bhat,
Physics is completely foreign to me. Please elaborate. If I use tan(theta)=y/x, what do I plus in for y and x? Also, how can I find final displacement (in km) from the origin?
1. You are given three vectors of lengths A=65.7, B=38.4, and C=43.7. The angles are theta a=29.1 degree and theta b=57.2 degree, and C points along the negative y-axis. (a) Determine the length of the vector A-B+C. (b) Calculate the angle of this vector
2.
(a) Rx = Ax-Bx+Cx Ry = Ay-By+Cy...
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[b]1. A delivery truck travels 10 km north, 18 km east, and 29 km south.
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b) What is the angle in degree of the final displacement relative to the east.
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