Recent content by benji123

So would it be... % change in n = % change in L - (4 times % change in d) % change in n = -2 - (4 times -2) % change in n = -2 +8 % change in n = + 6% Therefore, ±2% change in L and d = ±6% change in n?

What do I do with the relative error? As "Δd" will be 2% what will I use for "d" ?

Thanks for the reply Mark :) and correcting me with the dn/dA and dn/dd situation! I was wondering, how do I get the estimation when I have no values to work from for L and d?

Homework Statement Hi all! I am new to the forum, came across it from googling the problem which I had and someone was having difficuilty with a question like this on here! Here's the question I have... The coefficient of rigidity, n, of a wire of length L and uniform diameter d is given by...